# Problem Analysis:

The problem is to check whether the input alphabets is vowel or not by using if else and switch statements.

## Algorithm 1:  (using if else)

1.start

2.define :ch

3.Input; ch from the user.

4. If (ch==’a’//ch==’e’//ch==’i’//ch==’o’//ch==’u’

//ch==’A’//ch==’E’//ch==’I’//ch==’O’//ch==’U’)

print the vowel else nothing.

5. Output:vowel.

6.End

## Algorithm 2: (using switch)

1.start

2.Define :ch

3.Input ch from the user.

4.Switch (ch);

case ‘a’:, case’e’:, case’i’:,case’o’:

,case’u’:,case’A’:.case’E’:,case’I’:,case’O’:,case’U’:

print as vowel else default as nothing.

5.output the vowel.

6.End

## Outputs:

Compiling  ,  Debuggings   and Testings.

Enter character : a     a is a vowel.

## Codes 2:( using switch)

#include<stdio.h>

#include<conio.h>

void main()

{

char ch;

printf(“enter character:”);

scanf(“%C”,&ch);

switch(ch)

{

case ‘a’:

case’e’:

case’i’:

case’o’:

case’u’:

case’A’:

case’E’:

case’I’:

case’O’:

case’U’:

printf(“vowel \”);

break;

{

default:

printf(“not vowel’);

getch():

}

## Outputs:

Compiling  , Debugging  and Testings.

Enter character : a

a is vowel

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