# Problem Analysis:

The problem is to get the input of two or higher digit integer number and display in reverse order.

i.e. digit = num%10;

rev= rev*10 + digit;

num= num/10;

Input variables               Processing variables                     Output variables                         Necessary header files

num(long int)                       digit=num%10;                          rev(long int)                              stdio.h

rev=0(long int)                     rev=rev*10+ digit;                                                                       conio.h

digit(int)                               num=num/10;

## Algorithms:

1.start

2.Define :num,rev=0,digit.

3.Input : num by the user.

4.While (num!=0)

digit=num%10;

rev=rev*10+digit;

num=num/10

5.Print the output as rev.

6.End.

## Outputs :

Compiling  ,  Debugging  and Testing

Enter number: 589

so reverse is 985

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